60p^2-28p-16=0

Solution for 60p^2-28p-16=0 equation:

60p^2-28p-16=0

a = 60; b = -28; c = -16;
Δ = b2-4ac
Δ = -282-4·60·(-16)
Δ = 4624
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4624}=68$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-28)-68}{2*60}=\frac{-40}{120}
=-1/3
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-28)+68}{2*60}=\frac{96}{120}
=4/5
$